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Question Number 171342 by mathlove last updated on 13/Jun/22

Commented by infinityaction last updated on 13/Jun/22

$$3$$

Answered by Rasheed.Sindhi last updated on 13/Jun/22

$$A=1!+2!+3!+4!+\underset{duisibleby5}{\underbrace{5!+6!...+1000!}}$$$$A\equiv 1!+2!+3!+4!=33\left(mod5\right)$$$$A\equiv 3\left(mod5\right)$$

Commented by mathlove last updated on 13/Jun/22

$$thanks$$

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