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Question Number 171346 by Mr.D.N. last updated on 13/Jun/22

$$\mathrm{solve}:$$$$\frac{\mathrm{m}+{\left({\mathrm{mn}}^2\right)}^{1/3}+{\left({\mathrm{m}}^2\mathrm{n}\right)}^{1/3}}{\mathrm{m}-\mathrm{n}}\times \frac{({\mathrm{m}}^{1/3}-{\mathrm{n}}^{1/3})}{{\mathrm{m}}^{1/3}}$$

Commented by infinityaction last updated on 13/Jun/22

$$\frac{\cancel{m^{1/3}}\{m^{2/3}+n^{2/3}+{\left(mn\right)}^{1/3}\}}{m-n}\times \frac{m^{1/3}-n^{1/3}}{\cancel{m^{1/3}}}$$$$\frac{{\left\{m^{1/3}\right\}}^3-{\left\{n^{1/3}\right\}}^3}{m-n}$$$$\cancel{\frac{m-n}{m-n}}=1$$

Commented by Mr.D.N. last updated on 13/Jun/22

$$\mathrm{thank}\mathrm{you}.\mathrm{great}$$

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