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Question Number 171379 by mathlove last updated on 14/Jun/22

$$f\left(x\right)=\{\begin{array}{l}2x+3;x>0\\ 3x-5;x⩽0\end{array}$$ $$\frac{df\left(x\right)}{dx}=?$$

Commented byMJS_new last updated on 14/Jun/22

$$f\left(x\right)=\{\begin{array}{l}3x-5;x⩽0\\ \mathrm{not}\mathrm{defined};0<x⩽2\\ 2x+3;x>2\end{array}$$ $$f{}^{\prime }\left(x\right)=\{\begin{array}{l}3;x⩽0\\ \mathrm{not}\mathrm{defined};0<x⩽2\\ 2;x>2\end{array}$$

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