ax+by+cz=(2/3) x+y+z=18 (1/a)+(1/b)+(1/c)=?


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Question Number 171397 by mathlove last updated on 14/Jun/22

$a x + b y + c z = \frac{2}{3}$ $x + y + z = 18$ $\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = ?$
Commented by mr W last updated on 14/Jun/22

$2 e q u a t i o n s f o r 6 v a r i a b l e s,$ $\Rightarrow y o u c a n g e t a n y v a l u e f o r a, b, c .$
Commented by mr W last updated on 14/Jun/22

$d i d y o u c r e a t e t h e q u e s t i o n s o r y o u$ $g o t t h e m s o m e w h e r e ?$
Commented by MJS_new last updated on 15/Jun/22

${it}^{'} s not mathematics, {it}^{'} s a game$ $let a = b = c = \frac{1}{27}$ $\Rightarrow \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = 81$
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