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Question Number 171456 by mathlove last updated on 15/Jun/22

Commented by mathlove last updated on 16/Jun/22

$s o l u t i o n ? ?$
	Answered by Rasheed.Sindhi last updated on 16/Jun/22

	$L e t P (x) = {a x}^{2} + b x + c$ $∙ P (x) i s d i v i d e d b y x - 3 l e a v i n g$ $r e m a i n d e r 4 . B y s y n t h e t i c d i v i s i o n :$ $\begin{array}{ccc} 3) & a & b & c \\ 3 a & 9 a + 3 b \\ a & 3 a + b & 9 a + 3 b + c = 4^{★} \end{array}$ $Q (x) = a x + (3 a + b)$ $∙ Q (x) i s d i v i d e d b y x + 3 l e a v i n g$ $r e m a i n d e r (R) 2 .$ $R = Q (- 3) = a (- 3) + (3 a + b) = 2$ $b = 2$ $^{★} 9 a + 3 (2) + c = 4 \Rightarrow 9 a + c = - 2$ $∙ P (x) i s d i v i d e d b y x^{2} - 9$ $x^{2} - 9) \overset{a}{{a x}^{2} + b x + c}$ $_{-} {a x}^{2} \underset{+}{-} 9 a$ $R e m a i n d e r : b x + 9 a + c = (2) x + (- 2)$ $= 2 x - 2 a n s$
	Commented by mathlove last updated on 16/Jun/22

	$t h a n k s$
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