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Question Number 17153 by Tinkutara last updated on 01/Jul/17

$$\mathrm{If}m,n\in N(n>m),\mathrm{then}\mathrm{number}\mathrm{of}$$ $$\mathrm{solutions}\mathrm{of}\mathrm{the}\mathrm{equation}$$ $$n\mid \sin x\mid =m\mid \sin x\mid \mathrm{in}[0,2\pi ]\mathrm{is}$$

Answered by mrW1 last updated on 01/Jul/17

$$n\mid \sin x\mid =m\mid \sin x\mid$$ $$\because \mathrm{m}\ne \mathrm{n}$$ $$\therefore \mid \sin \mathrm{x}\mid =0$$ $$\mathrm{x}=0,\pi ,2\pi$$ $$\Rightarrow \mathrm{there}\mathrm{are}3\mathrm{solutions}$$

Commented byTinkutara last updated on 02/Jul/17

$$\mathrm{Thanks}\mathrm{Sir}!$$

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