Question Number 171546 by Kodjo last updated on 17/Jun/22
$${f}\left({x}\right)=\frac{−{ln}\mid{x}\mid}{{x}}+{x}−\mathrm{2}\:\:,\:\:\:{g}\left({x}\right)=−{x}^{\mathrm{2}} +\mathrm{1}−{ln}\mid{x}\mid \\ $$ $$ \\ $$ Calculate the derivative of f(x) as a function of g(x)\\n
Commented bykaivan.ahmadi last updated on 17/Jun/22
$${f}\left({x}\right)=\frac{−{lnx}+{x}^{\mathrm{2}} −\mathrm{2}{x}}{{x}}=\frac{{g}\left({x}\right)+{x}^{\mathrm{2}} −\mathrm{1}+{x}^{\mathrm{2}} −\mathrm{2}{x}}{{x}} \\ $$ $$=\frac{{g}\left({x}\right)−\mathrm{2}{x}−\mathrm{1}}{{x}}=\frac{{g}\left({x}\right)}{{x}}−\mathrm{2}−\frac{\mathrm{1}}{{x}} \\ $$ $${f}'\left({x}\right)=\frac{{xg}'\left({x}\right)−{g}\left({x}\right)}{{x}^{\mathrm{2}} }+\frac{\mathrm{1}}{{x}^{\mathrm{2}} }=\frac{{xg}'\left({x}\right)−{g}\left({x}\right)+\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$