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Question Number 171677 by cherokeesay last updated on 19/Jun/22

Answered by mr W last updated on 19/Jun/22

R=2r  rectangle a×b with b=2r  a=(√((r+R)^2 −r^2 ))=2(√2)r  shaded area=ab−((πr^2 )/2)−((πR^2 )/4)=ab−((3πr^2 )/2)  %=1−((3πr^2 )/(2ab))=1−((3πr^2 )/(2×2r×2(√2)r))      =1−((3π)/(8(√2)))=17%

R=2rrectanglea×bwithb=2ra=(r+R)2r2=22rshadedarea=abπr22πR24=ab3πr22%=13πr22ab=13πr22×2r×22r=13π82=17%

Commented by Tawa11 last updated on 19/Jun/22

Great sir

Greatsir

Commented by cherokeesay last updated on 19/Jun/22

thank you sir !

thankyousir!

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