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Question Number 171706 by Haisokheng last updated on 20/Jun/22
Answered by cortano1 last updated on 20/Jun/22
Answered by thfchristopher last updated on 20/Jun/22
limx→11−x3cosπx+1=limx→1−3x2π(x+1)2sinπx+1=−3π4=−12π
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