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Question Number 171801 by Mastermind last updated on 21/Jun/22

$$\mathrm{Two}\mathrm{numbers}\mathrm{are}\mathrm{respectively}20\mathrm{\%}\mathrm{and}$$$$10\mathrm{\%}\mathrm{more}\mathrm{than}\mathrm{a}\mathrm{third}\mathrm{number}.\mathrm{How}$$$$\mathrm{much}\mathrm{percent}\mathrm{is}\mathrm{the}\mathrm{first}\mathrm{number}\mathrm{more}$$$$\mathrm{than}\mathrm{the}\mathrm{second}?$$$$$$$$\mathrm{Mastermind}$$

Answered by thfchristopher last updated on 21/Jun/22

$$\mathrm{Let}a,b\mathrm{and}c\mathrm{be}\mathrm{the}\mathrm{three}\mathrm{numbers}\mathrm{in}\mathrm{order}\mathrm{such}\mathrm{that}:$$$$a=1.2c$$$$b=1.1c$$$$\therefore \frac{1.2c-1.1c}{1.1c}$$$$\approx 0.091$$$$\mathrm{The}\mathrm{first}\mathrm{number}\mathrm{is}9.1\mathrm{\%}\mathrm{greater}\mathrm{than}\mathrm{the}\mathrm{second}\mathrm{number}$$

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