Question Number 171822 by Mikenice last updated on 21/Jun/22 | ||
$${solve}\:{for}\:{x}: \\ $$$${x}^{{x}^{{x}^{\mathrm{2017}} } } =\mathrm{2017} \\ $$ | ||
Commented by mr W last updated on 21/Jun/22 | ||
$$\Rightarrow{x}^{\mathrm{2017}} =\mathrm{2017} \\ $$$$\Rightarrow{x}=\sqrt[{\mathrm{2017}}]{\mathrm{2017}} \\ $$ | ||