solve for x: 2log_x 4=log


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Question Number 171828 by Mikenice last updated on 21/Jun/22

$s o l v e f o r x :$ $2 {l o g}_{x} 4 = {l o g}_{2} x$
Commented by kaivan.ahmadi last updated on 21/Jun/22
$log_x 16=log_2 x⇒((log_2 16)/(log_2 x))=log_2 x⇒ 4=(log_2 x)^2 ⇒{_(log_2 x=−2⇒x=(1/4)) ^(log_2 x=2⇒x=4)$
${l o g}_{x} 16 = {l o g}_{2} x \Rightarrow \frac{{l o g}_{2} 16}{{l o g}_{2} x} = {l o g}_{2} x \Rightarrow$ $4 = {({l o g}_{2} x)}^{2} \Rightarrow {_{{l o g}_{2} x = - 2 \Rightarrow x = \frac{1}{4}}^{{l o g}_{2} x = 2 \Rightarrow x = 4}$
Commented by Mikenice last updated on 21/Jun/22

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