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Question Number 172005 by Mikenice last updated on 23/Jun/22

find x: (log_(10) x)^2 −log_(10) x=0

findx:(log10x)2−log10x=0

Answered by puissant last updated on 23/Jun/22

X=log_(10) x ⇒ X^2 −X=0 ⇒ X(X−1)=0 ⇒ X=0 or X=1 log_(10) x = ((lnx)/(ln10))=0 ⇒ lnx=0 ⇒ x=1 log_(10) x=((lnx)/(ln10))=1 ⇒ lnx=ln10 ⇒ x=10.

X=log10x⇒X2−X=0⇒X(X−1)=0⇒X=0orX=1log10x=lnxln10=0⇒lnx=0⇒x=1log10x=lnxln10=1⇒lnx=ln10⇒x=10.

Answered by Rasheed.Sindhi last updated on 23/Jun/22

find x: (log_(10) x)^2 −log_(10) x=0 log_(10) x (log_(10) x−1)=0 log_(10) x=0 ∣ log_(10) x=1 x=10^0 ∣ x=10^1 x=1, 10

findx:(log10x)2−log10x=0log10x(log10x−1)=0log10x=0∣log10x=1x=100∣x=101x=1,10

Commented by Mikenice last updated on 23/Jun/22

yhanks sir

yhankssir

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