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Question Number 172152 by Giantyusuf last updated on 23/Jun/22

Answered by Rasheed.Sindhi last updated on 23/Jun/22

h: first digit(hundred) t: second digit(ten) u: third digit(unit) t=4u h=t−3=4u−3 (h,t,u)=(4u−3,4u,u) possible values for u: 0,1,2 If u=0 ,h=−3(rejected) (h,t,u)=(4u−3,4u,u) =(1,4,1),(5,8,2) ∴ The required number: 141 or 582

$${h}:\:{first}\:{digit}\left({hundred}\right) \\ $$$${t}:\:{second}\:{digit}\left({ten}\right) \\ $$$${u}:\:{third}\:{digit}\left({unit}\right) \\ $$$${t}=\mathrm{4}{u} \\ $$$${h}={t}−\mathrm{3}=\mathrm{4}{u}−\mathrm{3} \\ $$$$\left({h},{t},{u}\right)=\left(\mathrm{4}{u}−\mathrm{3},\mathrm{4}{u},{u}\right) \\ $$$${possible}\:{values}\:{for}\:{u}:\:\mathrm{0},\mathrm{1},\mathrm{2} \\ $$$${If}\:{u}=\mathrm{0}\:,{h}=−\mathrm{3}\left({rejected}\right) \\ $$$$\left({h},{t},{u}\right)=\left(\mathrm{4}{u}−\mathrm{3},\mathrm{4}{u},{u}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\left(\mathrm{1},\mathrm{4},\mathrm{1}\right),\left(\mathrm{5},\mathrm{8},\mathrm{2}\right) \\ $$$$\therefore\:\mathcal{T}{he}\:{required}\:{number}:\:\mathrm{141}\:{or}\:\mathrm{582} \\ $$

Commented by peter frank last updated on 24/Jun/22

thanks

$$\mathrm{thanks} \\ $$

Commented by Rasheed.Sindhi last updated on 25/Jun/22

thanks to you too

$$\mathrm{thanks}\:\mathrm{to}\:\mathrm{you}\:\mathrm{too} \\ $$

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