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Question Number 172261 by Mikenice last updated on 25/Jun/22

Answered by Rasheed.Sindhi last updated on 25/Jun/22

$${(4\sqrt{3}+7)}^{2016}{(4\sqrt{3}-7)}^{2016}$$$$={\left\{(4\sqrt{3}+7)(4\sqrt{3}-7)\right\}}^{2016}$$$$={\{{\left(4\sqrt{3}\right)}^2-7^2\}}^{2016}$$$$={\{16\left(3\right)-49\}}^{2016}$$$$={\{-1\}}^{2016}$$$$=1$$

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