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Question Number 172483 by mnjuly1970 last updated on 27/Jun/22

Answered by mr W last updated on 28/Jun/22

Commented by mr W last updated on 28/Jun/22

$$set\mathrm{\angle }BCE=\alpha$$$$\Rightarrow \stackrel{⌢}{EB}=\stackrel{⌢}{CA}$$$$\stackrel{⌢}{CAE}=\stackrel{⌢}{CA}+\stackrel{⌢}{AE}=\stackrel{⌢}{EB}+\stackrel{⌢}{AE}=\stackrel{⌢}{AEB}$$$$\Rightarrow CE=AB$$$$\mathrm{\angle }CED=90°$$$$CE=CD\cos (\theta +\alpha )$$$$\Rightarrow AB=CD\cos (\theta +\alpha )✓$$

Commented by Tawa11 last updated on 28/Jun/22

$$\mathrm{Great}\mathrm{sir}.$$

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