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Question Number 172687 by Rasheed.Sindhi last updated on 30/Jun/22

Sum to n terms: 7+77+777+...

$$\mathrm{Sum}\:\mathrm{to}\:\mathrm{n}\:\mathrm{terms}: \\ $$$$\mathrm{7}+\mathrm{77}+\mathrm{777}+... \\ $$

Commented by mr W last updated on 30/Jun/22

S=1+11+111+...+111∙∙∙1_(n times) 10S=10+110+1110+...+111∙∙∙1_(n times) 0 −9S=n−10×111∙∙∙1_(n times) S=(10×111∙∙∙1_(n times) −n)/9 7+77+777+... =7(1+11+111+...) =7S =(7/9)(10×111∙∙∙1_(n times) −n)

$${S}=\mathrm{1}+\mathrm{11}+\mathrm{111}+...+\underset{{n}\:{times}} {\mathrm{111}\centerdot\centerdot\centerdot\mathrm{1}} \\ $$$$\mathrm{10}{S}=\mathrm{10}+\mathrm{110}+\mathrm{1110}+...+\underset{{n}\:{times}} {\mathrm{111}\centerdot\centerdot\centerdot\mathrm{1}0} \\ $$$$−\mathrm{9}{S}={n}−\mathrm{10}×\underset{{n}\:{times}} {\mathrm{111}\centerdot\centerdot\centerdot\mathrm{1}} \\ $$$${S}=\left(\mathrm{10}×\underset{{n}\:{times}} {\mathrm{111}\centerdot\centerdot\centerdot\mathrm{1}}−{n}\right)/\mathrm{9} \\ $$$$ \\ $$$$\mathrm{7}+\mathrm{77}+\mathrm{777}+... \\ $$$$=\mathrm{7}\left(\mathrm{1}+\mathrm{11}+\mathrm{111}+...\right) \\ $$$$=\mathrm{7}{S} \\ $$$$=\frac{\mathrm{7}}{\mathrm{9}}\left(\mathrm{10}×\underset{{n}\:{times}} {\mathrm{111}\centerdot\centerdot\centerdot\mathrm{1}}−{n}\right) \\ $$

Commented by Rasheed.Sindhi last updated on 30/Jun/22

ThanX sir!

$$\mathcal{T}{han}\mathcal{X}\:{sir}! \\ $$

Commented by Tawa11 last updated on 01/Jul/22

Great sir

$$\mathrm{Great}\:\mathrm{sir} \\ $$

Answered by som(math1967) last updated on 30/Jun/22

7(1+11+111+...) (7/9)(9+99+999+...) (7/9)(10−1+10^2 −1+10^3 −1+...) (7/9){(10+10^2 +10^3 +...)−1×n} (7/9)×((10(10^n −1))/(10−1)) −((7n)/9) ((70(10^n −1))/(81)) −((7n)/9)

$$\mathrm{7}\left(\mathrm{1}+\mathrm{11}+\mathrm{111}+...\right) \\ $$$$\frac{\mathrm{7}}{\mathrm{9}}\left(\mathrm{9}+\mathrm{99}+\mathrm{999}+...\right) \\ $$$$\frac{\mathrm{7}}{\mathrm{9}}\left(\mathrm{10}−\mathrm{1}+\mathrm{10}^{\mathrm{2}} −\mathrm{1}+\mathrm{10}^{\mathrm{3}} −\mathrm{1}+...\right) \\ $$$$\frac{\mathrm{7}}{\mathrm{9}}\left\{\left(\mathrm{10}+\mathrm{10}^{\mathrm{2}} +\mathrm{10}^{\mathrm{3}} +...\right)−\mathrm{1}×{n}\right\} \\ $$$$\frac{\mathrm{7}}{\mathrm{9}}×\frac{\mathrm{10}\left(\mathrm{10}^{{n}} −\mathrm{1}\right)}{\mathrm{10}−\mathrm{1}}\:−\frac{\mathrm{7}{n}}{\mathrm{9}} \\ $$$$\:\frac{\mathrm{70}\left(\mathrm{10}^{{n}} −\mathrm{1}\right)}{\mathrm{81}}\:−\frac{\mathrm{7}{n}}{\mathrm{9}} \\ $$

Commented by Rasheed.Sindhi last updated on 30/Jun/22

Thanks sir!

$$\mathbb{T}\mathrm{han}\Bbbk\mathrm{s}\:\mathrm{sir}! \\ $$

Commented by Tawa11 last updated on 01/Jul/22

Great sir

$$\mathrm{Great}\:\mathrm{sir} \\ $$

Commented by peter frank last updated on 03/Jul/22

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

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