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Question Number 172740 by SANOGO last updated on 30/Jun/22

Commented by Rasheed.Sindhi last updated on 30/Jun/22

$C o u l d y o u p l e a s e t r a n s l a t e i n t o$ $E n g l i s h ?$
	Answered by JDamian last updated on 01/Jul/22
	$(2) ((n^2 −3n+6)/(n−1))=((n^2 −n−2n+6)/(n−1))= =n+((−2n+6)/(n−1))=n−2+(4/(n−1)) ∣n−1∣ ∈ {1, 2, 4} n∈{−3, −1, 0, 2, 3, 5}$
	$(2)$ $\frac{n^{2} - 3 n + 6}{n - 1} = \frac{n^{2} - n - 2 n + 6}{n - 1} =$ $= n + \frac{- 2 n + 6}{n - 1} = n - 2 + \frac{4}{n - 1}$ $∣ n - 1 ∣ \in {1, 2, 4}$ $n \in {- 3, - 1, 0, 2, 3, 5}$
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