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Question Number 172984 by dragan91 last updated on 04/Jul/22
Answered by Mathspace last updated on 04/Jul/22
Υ1+Υ2=∫01ln(x+x+1)(x−x+1)dx=∫01ln(x−x−1)dx=∫01ln(−1)dx=∫01ln(eiπ)dx=iπ∫01dx=iπ
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