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Question Number 173000 by Mikenice last updated on 04/Jul/22

Commented by MJS_new last updated on 04/Jul/22

$$2^{x+y}=6\Rightarrow x+y=\frac{\ln 6}{\ln 2}=a$$$$3^{x+y}=4\Rightarrow x+y=\frac{\ln 4}{\ln 3}=b$$$$a\ne b\Rightarrow \mathrm{no}\mathrm{solution}$$

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