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Question Number 17313 by Arnab Maiti last updated on 03/Jul/17

$$\mathrm{Why}\mathrm{magnetic}\mathrm{force}\left(\overrightarrow{\mathrm{F}}\right)\mathrm{on}\mathrm{a}\mathrm{moving}\mathrm{charge}$$$$\mathrm{q}\mathrm{having}\mathrm{velocity}\mathrm{v}\mathrm{is}\mathrm{q}\left(\overrightarrow{\mathrm{v}}\times \overrightarrow{\mathrm{B}}\right)?$$

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