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Question Number 173165 by mr W last updated on 07/Jul/22

$${what}^{\prime }sthelargestnumberyoucan$$$$formonlyusingthedigits1,2,3,4?$$

Answered by pnuvu last updated on 07/Jul/22

$$4^{3^{(2+1)}}$$

Answered by mr W last updated on 08/Jul/22

$$2^{3^{41}}or{3}^{2^{41}}or{4}^{2^{31}}?$$$$2^{3^{41}}=4^{\frac{3^{41}}{2}}>3^{\frac{3^{41}}{2}}>3^{\frac{1.5^{41}}{2}\times 2^{41}}>3^{2^{41}}$$$$2^{3^{41}}=4^{\frac{3^{41}}{2}}>4^{2^{31}}$$$$sothelargestnumberis{2}^{3^{41}}.$$

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