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Question Number 173504 by AgniMath last updated on 12/Jul/22

	Answered by behi834171 last updated on 12/Jul/22

	$A = \sqrt{x} + \frac{1}{\sqrt{x}} \Rightarrow A^{2} = x + \frac{1}{x} + 2 = 4 \Rightarrow A = 2 . ◼$
	Commented by Rasheed.Sindhi last updated on 12/Jul/22

	$W e l c o m e A b u B e h i s i r a f t e r l o n g t i m e!$
	Commented by behi834171 last updated on 12/Jul/22

	$h e l l o m r r a s h e e d . t h a n k y o u s o m u c h d u e$ $t o w a r m w e l c o m e . m i s y o u a n d a l l o f$ $m y d e a r f r i e n d s a n d m a s t e r s .$ $I^{'} m h e r e f r o m n o w t o m u c h m o r e t i m e s$ $a f t e r .$
	Answered by MJS_new last updated on 12/Aug/22

	$x + \frac{1}{x} = 2 \Leftrightarrow x^{2} - 2 x + 1 = 0 \Leftrightarrow {(x - 1)}^{2} = 0 \Leftrightarrow x = 1$ $\Rightarrow answer is 2$ $x + \frac{1}{x} = a \Rightarrow \sqrt{x} + \frac{1}{\sqrt{x}} = \sqrt{a + 2}$
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