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Question Number 173535 by mnjuly1970 last updated on 13/Jul/22
Answered by mr W last updated on 13/Jul/22
inexpansionof(x1+x2+x3+...+xn)mthegeneraltermisx1k1x2k2x3k3...xnknwith0⩽ki⩽mandk1+k2+k3+...+kn=mthereareCmn−1+mpossibilities.i.e.thenumberofdistincttermsisCmn−1+m.incurrentcase:n=4,m=10numberofdistincttermsisC1013=286.
Commented by mnjuly1970 last updated on 13/Jul/22
thanksalotMasterW
Commented by Tawa11 last updated on 13/Jul/22
Greatsir.
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