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Question Number 173798 by payamnazerian last updated on 18/Jul/22

         ( ϕ^( 5) + ϕ^( 4) + 1)^( 2) = mϕ + n           m,n=?                 ........

(φ5+φ4+1)2=mφ+nm,n=?........

Answered by mr W last updated on 18/Jul/22

ϕ^2 −ϕ−1=0  ϕ^2 =ϕ+1  ϕ^3 =ϕ^2 +ϕ=2ϕ+1  ϕ^4 =2ϕ^2 +ϕ=3ϕ+2  ϕ^5 =3ϕ^2 +2ϕ=5ϕ+3  ϕ^5 +ϕ^4 +1=5ϕ+3+3ϕ+2+1=8ϕ+6  (ϕ^5 +ϕ^4 +1)^2 =64ϕ^2 +96ϕ+36  (ϕ^5 +ϕ^4 +1)^2 =64(ϕ+1)+96ϕ+36  (ϕ^5 +ϕ^4 +1)^2 =160ϕ+100=mϕ+n  ⇒m=160, n=100

φ2φ1=0φ2=φ+1φ3=φ2+φ=2φ+1φ4=2φ2+φ=3φ+2φ5=3φ2+2φ=5φ+3φ5+φ4+1=5φ+3+3φ+2+1=8φ+6(φ5+φ4+1)2=64φ2+96φ+36(φ5+φ4+1)2=64(φ+1)+96φ+36(φ5+φ4+1)2=160φ+100=mφ+nm=160,n=100

Commented by Tawa11 last updated on 18/Jul/22

Great sir

Greatsir

Commented by mnjuly1970 last updated on 18/Jul/22

    grateful sir

gratefulsir

Answered by Rasheed.Sindhi last updated on 18/Jul/22

Another way   ( ϕ^( 5) + ϕ^( 4) + 1)^( 2) = mϕ + n; m,n=?    ϕ^2 −ϕ−1=0⇒ϕ^2 =ϕ+1⇒ϕ^2 −1=ϕ    ϕ^( 5) + ϕ^( 4) + 1=ϕ^( 4) (ϕ+1)+1  =ϕ^4 ϕ^2 +1=ϕ^6 +1  =(ϕ^2 +1)(ϕ^4 −ϕ^2 +1)  =(ϕ^2 −1+2)(ϕ^2 (ϕ^2 −1)+1)  =(ϕ+2){ϕ(ϕ+1)+1}  =(ϕ+2)(ϕ^2 +ϕ+1)  =(ϕ+2)(ϕ^2 −ϕ−1+2ϕ+2)  =(ϕ+2)(0+2ϕ+2)  =2ϕ^2 +6ϕ+4  =2(ϕ+1)+6ϕ+4  =8ϕ+6  (ϕ^( 5) + ϕ^( 4) + 1)^2 =(8ϕ+6)^2      =64ϕ^2 +96ϕ+36     =64(ϕ+1)+96ϕ+36     =160ϕ+100  m=160,n=100

Anotherway(φ5+φ4+1)2=mφ+n;m,n=?φ2φ1=0φ2=φ+1φ21=φφ5+φ4+1=φ4(φ+1)+1=φ4φ2+1=φ6+1=(φ2+1)(φ4φ2+1)=(φ21+2)(φ2(φ21)+1)=(φ+2){φ(φ+1)+1}=(φ+2)(φ2+φ+1)=(φ+2)(φ2φ1+2φ+2)=(φ+2)(0+2φ+2)=2φ2+6φ+4=2(φ+1)+6φ+4=8φ+6(φ5+φ4+1)2=(8φ+6)2=64φ2+96φ+36=64(φ+1)+96φ+36=160φ+100m=160,n=100

Commented by mnjuly1970 last updated on 19/Jul/22

  thanks alot sir

thanksalotsir

Answered by Rasheed.Sindhi last updated on 18/Jul/22

Still another way  ϕ^2 −ϕ−1=0  ϕ^2 =ϕ+1  ϕ^2 +ϕ=2ϕ+1  ϕ^5 +ϕ^4 =ϕ^3 (2ϕ+1)               =ϕ^2 (2ϕ^2 +ϕ)               =(ϕ+1)( 2(ϕ+1)+ϕ )              =(ϕ+1)( 3ϕ+2)              =3ϕ^2 +5ϕ+2              =3(ϕ+1)+5ϕ+2   ϕ^5 +ϕ^4 +1=8ϕ+5+1=8ϕ+6   (ϕ^5 +ϕ^4 +1)^2 =(8ϕ+6)^2                              =64ϕ^2 +96ϕ+36                             =64(ϕ+1)+96ϕ+36                           =160ϕ+100        m=160,n=100

Stillanotherwayφ2φ1=0φ2=φ+1φ2+φ=2φ+1φ5+φ4=φ3(2φ+1)=φ2(2φ2+φ)=(φ+1)(2(φ+1)+φ)=(φ+1)(3φ+2)=3φ2+5φ+2=3(φ+1)+5φ+2φ5+φ4+1=8φ+5+1=8φ+6(φ5+φ4+1)2=(8φ+6)2=64φ2+96φ+36=64(φ+1)+96φ+36=160φ+100m=160,n=100

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