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Question Number 174406 by Best1 last updated on 31/Jul/22

Answered by alephzero last updated on 31/Jul/22

$${\int }_0^1(4\sqrt{1-x^2}+2)\mathrm{d}x=$$$$4{\int }_0^1\sqrt{1-x^2}\mathrm{d}x+{\int }_0^{1}2\mathrm{d}x=\pi +2$$$$\mathrm{A}.$$

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