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Question Number 174487 by mnjuly1970 last updated on 02/Aug/22

Answered by dragan91 last updated on 02/Aug/22

$$$$$${\mathrm{x}}^2-25\mathrm{x}=\mathrm{x}+5\sqrt{\mathrm{x}}$$$$\mathrm{x}(\mathrm{x}-25)=\sqrt{\mathrm{x}}(\sqrt{\mathrm{x}}+5)$$$$\mathrm{x}(\sqrt{\mathrm{x}}-5)(\sqrt{\mathrm{x}}+5)=\sqrt{\mathrm{x}}(\sqrt{\mathrm{x}}+5)$$$$\mathrm{x}(\sqrt{\mathrm{x}}-5)=\sqrt{\mathrm{x}}/:\sqrt{\mathrm{x}}$$$$\sqrt{\mathrm{x}}(\sqrt{\mathrm{x}}-5)=1$$$$\mathrm{x}-5\sqrt{\mathrm{x}}=1/.5$$$$5\mathrm{x}-25\sqrt{\mathrm{x}}=5\mathrm{for}\mathrm{x}\ne 0$$

Commented by mnjuly1970 last updated on 03/Aug/22

$$verynicesolutionthxalot$$$$sirdragan$$

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