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Question Number 174569 by behi834171 last updated on 04/Aug/22

$$\{\begin{array}{l}\mathit{x}+\mathit{z}=0\\ \mathit{y}+\mathit{t}+\mathit{x}\mathit{z}=-2\mathit{b}\\ \mathit{x}\mathit{t}+\mathit{y}\mathit{z}=1\\ \mathit{y}\mathit{t}={\mathit{b}}^2-\mathit{a}\end{array}[\mathit{a}\mathit{l}\mathit{l}\in \mathit{R}]$$$$\mathit{s}\mathit{o}\mathit{l}\mathit{v}\mathit{e}\mathit{f}\mathit{o}\mathit{r}:\mathit{x},\mathit{y},\mathit{z},\mathit{t}.$$

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