Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 174576 by othman last updated on 04/Aug/22

Answered by Ar Brandon last updated on 04/Aug/22

$$t=w^2-4\Rightarrow dt=2wdw$$$$2{\int }_{-3}^0\frac{1}{\sqrt[3]{t}}dt=3{\left[t^{2/3}\right]}_{-3}^0=-3\sqrt[3]{9}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com