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Question Number 174655 by AgniMath last updated on 06/Aug/22

$$\mathrm{Factorize}{a}^3-16a-3$$

Answered by MJS_new last updated on 07/Aug/22

$$\mathrm{LOL}!$$$$a^3-16a-3=$$$$=(a+\frac{8\sqrt{3}}{3}\cos (\frac{\pi }{6}+\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128}))(a+\frac{8\sqrt{3}}{3}\sin \left(\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128}\right))(a-\frac{8\sqrt{3}}{3}\sin (\frac{\pi }{3}+\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128}))$$$$\mathrm{I}\mathrm{hope}{\mathrm{you}}^{\prime }\mathrm{re}\mathrm{satisfied}!$$

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