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Question Number 174689 by daus last updated on 08/Aug/22

Commented by daus last updated on 08/Aug/22

please help me at C question

$${please}\:{help}\:{me}\:{at}\:{C}\:{question} \\ $$

Commented by mahdipoor last updated on 08/Aug/22

a_n = { ((0    if 2∣n)),(((((n+3)/2)/((n+5)/2))=((n+3)/(n+5))     2∤n      )) :}

$${a}_{{n}} =\begin{cases}{\mathrm{0}\:\:\:\:{if}\:\mathrm{2}\mid{n}}\\{\frac{\left({n}+\mathrm{3}\right)/\mathrm{2}}{\left({n}+\mathrm{5}\right)/\mathrm{2}}=\frac{{n}+\mathrm{3}}{{n}+\mathrm{5}}\:\:\:\:\:\mathrm{2}\nmid{n}\:\:\:\:\:\:}\end{cases} \\ $$

Commented by Rasheed.Sindhi last updated on 10/Aug/22

a_n =(((1+(−1)^(n+1) )/2))(((n+3)/(n+5))) ; n∈{1,2,3,...}

$${a}_{{n}} =\left(\frac{\mathrm{1}+\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} }{\mathrm{2}}\right)\left(\frac{{n}+\mathrm{3}}{{n}+\mathrm{5}}\right)\:;\:{n}\in\left\{\mathrm{1},\mathrm{2},\mathrm{3},...\right\} \\ $$

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