where am i wrong ?


Question and Answers Forum

All Questions Topic List
Mechanics Questions
Previous in All Question Next in All Question
Previous in Mechanics Next in Mechanics
Question Number 174758 by Kallu last updated on 10/Aug/22

$w h e r e a m i w r o n g ?$
Commented by Kallu last updated on 10/Aug/22

$w h e r e a m i w r o n g ?$ $C o r r e c t a n s w e r i s 5 / 4$
Commented by Kallu last updated on 10/Aug/22

Commented by Kallu last updated on 10/Aug/22

	Answered by Ar Brandon last updated on 10/Aug/22

	$Σ F_{y} : W_{1} = W_{2} \cos 37 ° + T \cos 53 °$ $Σ F_{x} : T \sin 53 ° = W_{2} \sin 37 ° \Rightarrow T = \frac{\sin 37 °}{\sin 53 °} W_{2}$ $\Rightarrow W_{1} = W_{2} \cos 37 ° + \frac{\sin 37 °}{\sin 53 °} \times \cos 53 ° W_{2}$ $\Rightarrow \frac{W_{1}}{W_{2}} = \cos 37 ° + \frac{\sin 37 °}{\tan 53 °} \approx 1.2521 \approx 1.25 = \frac{5}{4}$
	Commented by Kallu last updated on 11/Aug/22

	$T h a n k s I f i g u r e d o u t m y m i s t a k e .$
	Commented by Tawa11 last updated on 12/Aug/22

	$Great sir$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum