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Question Number 174779 by mnjuly1970 last updated on 10/Aug/22
Commented by behi834171 last updated on 10/Aug/22
sir!yourusedfontsaretoosmall.pleasebefriendwithmyeyesanduselargerfonts.thanksinadvance.
Commented by mnjuly1970 last updated on 11/Aug/22
yessir...thanksalot...
Answered by behi834171 last updated on 10/Aug/22
cosA2=p(p−a)bcandsoonΠcosA2=pp(p−a)(p−b)(p−c)abc==p.Sabc=p4R=a+b+c8R=2RΣsinA8R⩽⩽14×3×32=338.◼[note:ΣsinA⩽3×sinπ3=332]
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