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Question Number 174800 by AgniMath last updated on 11/Aug/22

$$\mathrm{For}\mathrm{which}\mathrm{value}\mathrm{of}x\mathrm{this}\mathrm{cubic}\mathrm{equation}\mathrm{will}$$$$\mathrm{be}0?a^3-16a-3$$

Answered by MJS_new last updated on 11/Aug/22

$$a_1=-\frac{8\sqrt{3}}{3}\cos (\frac{\pi }{6}+\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128})$$$$a_2=-\frac{8\sqrt{3}}{3}\sin \left(\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128}\right)$$$$a_3=\frac{8\sqrt{3}}{3}\sin (\frac{\pi }{3}+\frac{1}{3}\arcsin \frac{9\sqrt{3}}{128})$$

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