Question Number 174859 by Shrinava last updated on 12/Aug/22
Commented by Frix last updated on 12/Aug/22
$$\frac{{a}}{{b}}={k}\:\Leftrightarrow\:{a}={bk}\:\mathrm{etc}.\:\Rightarrow\:{a}+\mathrm{2}{c}+\mathrm{3}{e}=\left({b}+\mathrm{2}{d}+\mathrm{3}{f}\right){k} \\ $$$$\mathrm{answer}\:\mathrm{is}\:{k} \\ $$
Answered by behi834171 last updated on 12/Aug/22
$$=\:\:\boldsymbol{{k}}\:\:.\blacksquare \\ $$$$\frac{\boldsymbol{{a}}}{\boldsymbol{{b}}}=\frac{\boldsymbol{{c}}}{\boldsymbol{{d}}}=\frac{\boldsymbol{{a}}+\boldsymbol{{c}}}{\boldsymbol{{b}}+\boldsymbol{{d}}}=\frac{\boldsymbol{{ma}}+\boldsymbol{{nc}}}{\boldsymbol{{mb}}+\boldsymbol{{nd}}}=...... \\ $$