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Question Number 174950 by Mastermind last updated on 14/Aug/22

$$\mathrm{Have}\mathrm{you}\mathrm{seen}\mathrm{this}\mathrm{method}\mathrm{of}\mathrm{solving}$$$$\mathrm{quadratic}\mathrm{problem}?$$$${\mathrm{x}}^2-\mathrm{x}-12=0$$$${\mathrm{y}}^{\prime }=\pm \sqrt{{\mathrm{b}}^2-4\mathrm{ac}}$$

Answered by peter frank last updated on 14/Aug/22

$$\frac{\mathrm{d}}{\mathrm{dx}}({\mathrm{x}}^2-\mathrm{x}-12)=\pm \sqrt{{\mathrm{b}}^2-4\mathrm{ac}}$$$$2\mathrm{x}-1=\pm \sqrt{1^2-4\times -12}$$$$2\mathrm{x}-1=\pm \sqrt{1+48}$$$$2\mathrm{x}-1=\pm \sqrt{49}$$$$2\mathrm{x}-1=\pm 7$$$$2\mathrm{x}=1\pm 7$$$$\mathrm{x}=\frac{1\pm 7}{2}$$

Commented by Tawa11 last updated on 14/Aug/22

$$\mathrm{Great}\mathrm{sir}.$$

Commented by Tawa11 last updated on 14/Aug/22

$$\mathrm{x}=\frac{1\pm 7}{2}$$$$\mathrm{x}=4\mathrm{or}-3$$

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