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Question Number 174963 by MikeH last updated on 14/Aug/22

Commented by thfchristopher last updated on 15/Aug/22

But there is no such option for 7.31...

$$\mathrm{But}\:\mathrm{there}\:\mathrm{is}\:\mathrm{no}\:\mathrm{such}\:\mathrm{option}\:\mathrm{for}\:\mathrm{7}.\mathrm{31}... \\ $$

Answered by a.lgnaoui last updated on 15/Aug/22

7,31

$$\mathrm{7},\mathrm{31} \\ $$

Answered by behi834171 last updated on 15/Aug/22

XY=b  ⇒XZ^2 =XY^2 +YZ^2 −2XY.YZ.cosY^�   ⇒5^2 =b^2 +b^2 −2b^2 cos40⇒  ⇒b^2 =((25)/(2(1−cos40)))⇒    b=7.31  .■

$${XY}={b} \\ $$$$\Rightarrow{XZ}^{\mathrm{2}} ={XY}^{\mathrm{2}} +{YZ}^{\mathrm{2}} −\mathrm{2}{XY}.{YZ}.\boldsymbol{{cos}}\overset{} {\boldsymbol{{Y}}} \\ $$$$\Rightarrow\mathrm{5}^{\mathrm{2}} ={b}^{\mathrm{2}} +{b}^{\mathrm{2}} −\mathrm{2}{b}^{\mathrm{2}} {cos}\mathrm{40}\Rightarrow \\ $$$$\Rightarrow\boldsymbol{{b}}^{\mathrm{2}} =\frac{\mathrm{25}}{\mathrm{2}\left(\mathrm{1}−\boldsymbol{{cos}}\mathrm{40}\right)}\Rightarrow\:\:\:\:\boldsymbol{{b}}=\mathrm{7}.\mathrm{31}\:\:.\blacksquare \\ $$

Commented by MikeH last updated on 15/Aug/22

thank you sir. I solved that and I was shock   that I was wrong

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{solved}\:\mathrm{that}\:\mathrm{and}\:\mathrm{I}\:\mathrm{was}\:\mathrm{shock}\: \\ $$$$\mathrm{that}\:\mathrm{I}\:\mathrm{was}\:\mathrm{wrong} \\ $$

Answered by mr W last updated on 15/Aug/22

XY=(5/(2 sin ((40°)/2)))≈7.31

$${XY}=\frac{\mathrm{5}}{\mathrm{2}\:\mathrm{sin}\:\frac{\mathrm{40}°}{\mathrm{2}}}\approx\mathrm{7}.\mathrm{31} \\ $$

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