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Question Number 174974 by sciencestudent last updated on 15/Aug/22

Answered by MikeH last updated on 15/Aug/22

$$\mathrm{total}\mathrm{resistance}=2.0+14.0+9.5=25.5\mathrm{\Omega }$$$$\mathrm{but}V=IR\Rightarrow I=\frac{V}{R}=\frac{9.0}{25.5}=0.35\mathrm{A}$$$$\mathrm{now}\mathrm{transversing}\mathrm{the}\mathrm{circuit},$$$$9.5(0.35)+14(0.35)+2.0(0.35)-9.0\approx 0.0V$$

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