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Question Number 175166 by cherokeesay last updated on 21/Aug/22

Answered by ajfour last updated on 22/Aug/22

let centre of required circle be (h,R) h=−(r/(2(√2)))=−4 ⇒ r=8(√2) (h−(r/( (√2))))^2 +((r/( (√2)))−R)^2 =R^2 ⇒ 16+(8−R)^2 =R^2 8(2R−8)=16 R=5

letcentreofrequiredcirclebe(h,R)h=−r22=−4⇒r=82(h−r2)2+(r2−R)2=R2⇒16+(8−R)2=R28(2R−8)=16R=5

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