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Question Number 201223 by Calculusboy last updated on 02/Dec/23
∫1+1+xdx
Answered by witcher3 last updated on 02/Dec/23
=∫21+x+1+x.dx21+x=2∫t2+tdt⇔∫2(t+12)2+34dteasyfromhere
Commented by Calculusboy last updated on 02/Dec/23
yessir
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