Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 175199 by cherokeesay last updated on 22/Aug/22

Answered by som(math1967) last updated on 23/Aug/22

Commented by som(math1967) last updated on 23/Aug/22

$$OLBTrectangle$$$$radoflargecircle=OT=BL=2+\frac{6}{2}=5$$$$OL=\sqrt{{ON}^2-{LN}^2}=\sqrt{5^2-3^2}=4$$$$now{(r+5)}^2={(4-r)}^2+6^2$$$$10r+25=16-8r+36$$$$\Rightarrow 18r=36-9$$$$\therefore r=\frac{27}{18}=\frac{3}{2}=1.5$$

Commented by cherokeesay last updated on 23/Aug/22

$$perfect$$$$thankyousir.$$

Commented by Tawa11 last updated on 23/Aug/22

$$\mathrm{Great}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com