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Question Number 175266 by oustmuchiya@gmail.com last updated on 25/Aug/22

$$\mathrm{Find}\mathrm{matrix}\mid \mathrm{A}\mid {\mathrm{A}}^{-1}$$$$\mathrm{given}\mathrm{that}\mathrm{matrix}$$$$\mathrm{A}=\left(\begin{array}{cccc}\sqrt{2}& -1& 1& 0\\ 4& 3& 2& -1\\ 0& 2& 3& 1\\ 1& -1& 0& 1\end{array}\right)$$$$\mathrm{using}\mathrm{row}\mathrm{operations}$$

Commented by kaivan.ahmadi last updated on 27/Aug/22

$$easy$$$$\mid A\mid .A^{-1}=\mid A\mid .\frac{1}{\mid A\mid }{A}^{\ast }=A^{\ast }=A_{ij}^T$$$$$$

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