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Question Number 175275 by mnjuly1970 last updated on 25/Aug/22

Answered by Rasheed.Sindhi last updated on 25/Aug/22

(−5, x+2y)∪(2x−y−4, 3) =(−5,a)∪(a,3) a=x+2y=2x−y−4=((−5+3)/2)=−1 a=−1 x+2y=−1 ∧ 2x−y−4=−1 x=1, y=−1 (−5, −1)∪(−1, 3) r=∣−1−(−5)∣=4 [ or r=∣−1−3∣=4 ] a=−1, r=4 x=1, y=−1

(−5,x+2y)∪(2x−y−4,3)=(−5,a)∪(a,3)a=x+2y=2x−y−4=−5+32=−1a=−1x+2y=−1∧2x−y−4=−1x=1,y=−1(−5,−1)∪(−1,3)r=∣−1−(−5)∣=4[orr=∣−1−3∣=4]a=−1,r=4x=1,y=−1

Commented by mnjuly1970 last updated on 26/Aug/22

tayeballah grateful sir

tayeballahgratefulsir

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