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Question Number 175294 by zzzrot last updated on 26/Aug/22

	Answered by Rasheed.Sindhi last updated on 26/Aug/22

	$I n t r i a n g l e :$ $a : t h e o p p o s i t e s i d e t o t h e a n g l e o f$ $m e a s u r e 30 .$ $c : h y p o t e n u s e = 2 a$ $a^{2} + 6^{2} = {(2 a)}^{2}$ $3 a^{2} = 36 \Rightarrow a = 2 \sqrt{3}$ $c = 2 a = 4 \sqrt{3}$ $T h e p e r i m e t e r$ $= 6 \times 3 + 2 \sqrt{3} + 4 \sqrt{3}$ $= 18 + 6 \sqrt{3}$
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