Solve it by horner′s method. (2x^3 y^2 +3x^2 y−4x+5y−12)÷(x−3)


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Question Number 175346 by sciencestudent last updated on 27/Aug/22

$S o l v e i t b y {h o r n e r}^{'} s m e t h o d .$ $(2 x^{3} y^{2} + 3 x^{2} y - 4 x + 5 y - 12) \div (x - 3)$
	Answered by cortano1 last updated on 28/Aug/22

	$\begin{array}{ccc} ∙ & 2 y^{2} & 3 y & - 4 & 5 y - 12 \\ 3 & * & 6 y^{2} & 18 y^{2} + 9 y & 54 y^{2} + 27 y - 12 \\ 2 y^{2} & 6 y^{2} + 3 y & 18 y^{2} + 9 y - 4 & \underset{r e m a i n d e r}{\underset{⏟}{54 y^{2} + 32 y - 24}} \end{array}$
	Commented by sciencestudent last updated on 30/Aug/22

	$w h a t i s t h e q u o t i e n t ?$
	Commented by sciencestudent last updated on 30/Aug/22

	$q u o t i e n t ?$
	Commented by sciencestudent last updated on 30/Aug/22

	$P l e a s e h e l p m e m r W!$
	Commented by cortano1 last updated on 30/Aug/22

	$t h e q u o t i e n t i s 2 y^{2} x^{2} + (6 y^{2} + 3 y) x + 18 y^{2} + 9 y - 4$
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