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Question Number 175449 by cherokeesay last updated on 30/Aug/22

Commented by som(math1967) last updated on 31/Aug/22

is r=7−3(√5)≈0.29 ?  (S_2 /S_1 ) =((π(.29)^2 )/π)×100=8.41% ?

isr=7350.29?S2S1=π(.29)2π×100=8.41%?

Answered by mr W last updated on 03/Sep/22

Commented by mr W last updated on 03/Sep/22

tan 2θ=(2/1)=2  ((2tan θ)/(1−tan^2  θ))=2  tan θ=((−1+(√5))/2)=(2/( (√5)+1))=(1/ϕ)  CD=(r/(tan θ))=ϕr  BF=DE=2−ϕr  AF=2−r  AB=2+r  (2+r)^2 =(2−r)^2 +(2−ϕr)^2   8r=4−4ϕr+ϕ^2 r^2   0=4−4(ϕ+2)r+ϕ^2 r^2   r=((2(ϕ+2)−4(√(ϕ+1)))/ϕ^2 )=((2(2−ϕ))/(ϕ+1))=7−3(√5)

tan2θ=21=22tanθ1tan2θ=2tanθ=1+52=25+1=1φCD=rtanθ=φrBF=DE=2φrAF=2rAB=2+r(2+r)2=(2r)2+(2φr)28r=44φr+φ2r20=44(φ+2)r+φ2r2r=2(φ+2)4φ+1φ2=2(2φ)φ+1=735

Commented by Tawa11 last updated on 15/Sep/22

Great sir

Greatsir

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