All Questions Topic List
Trigonometry Questions
Previous in All Question Next in All Question
Previous in Trigonometry Next in Trigonometry
Question Number 175544 by cortano1 last updated on 02/Sep/22
tan6(10°)+tan6(50°)+tan6(70°)=?
Commented by Frix last updated on 29/Jan/23
433
Answered by a.lgnaoui last updated on 03/Sep/22
posonst=tan(5°)tan10°=tan(2t)tan50°=tan(45°+t)tan70°=tan(45°+25°)t′=tan(25°)(2t1−t2)6+(1+t1−t)6+(1−t′1+t′)6=(11−t)6[26t6(11+t)6+(1+t)6]+(1−t′1+t′)6=1(1−t)6[64t6(1+t)6+(1+t)6]t=0,087t′=tan(25°)=2−1=0,414=1(0,913)6[64×(0,087)6(1,087)6+(1,087)6]+(0,586)68=2,847+0,05=2,897Resultat:tan10+tan50+tan70=2,897
Terms of Service
Privacy Policy
Contact: info@tinkutara.com