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Question Number 175553 by BHOOPENDRA last updated on 02/Sep/22

Answered by Frix last updated on 03/Sep/22

$$\underset{0}{\stackrel{1}{\int }}\frac{(x^n-1)(x-1)}{x^{n+3}-1}dx\stackrel{(\mathrm{let}t=\frac{1}{x})}{=}\underset{\mathrm{\infty }}{\stackrel{1}{\int }}\frac{(t^n-1)(t-1)}{t^{n+3}-1}dt$$$$\Rightarrow$$$$\mathrm{answer}\mathrm{is}0$$

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