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Question Number 175821 by daus last updated on 07/Sep/22

Commented by daus last updated on 07/Sep/22

$$helpmefora$$

Answered by Rasheed.Sindhi last updated on 07/Sep/22

$$\left(a\right)$$$$\underset{\times 2}{\underbrace{5x+3y=4}}\wedge 2y+4z=5$$$$\underset{\left(i\right)}{\underbrace{10x+6y=8}}\wedge \underset{\left(ii\right)}{\underbrace{2y+4z=5}}$$$$\left(i\right)+\left(ii\right):$$$$10x+8y+4z=13$$

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