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Question Number 175894 by cortano1 last updated on 09/Sep/22

Answered by mr W last updated on 09/Sep/22

Commented by mr W last updated on 09/Sep/22

$$a^2={10}^2+{(a-5)}^2$$$$\Rightarrow a=12.5$$$${(a+R)}^2=a^2+{(10-R)}^2$$$$(20+2a)R=100$$$$\Rightarrow R=\frac{100}{45}=\frac{20}{9}✓$$

Commented by cortano1 last updated on 10/Sep/22

$$\mathrm{nice}$$

Commented by Tawa11 last updated on 15/Sep/22

$$\mathrm{Great}\mathrm{sir}$$

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